Relationships between * and args

title: Relationships between * and args

Presence of * in function definition

# How does *args work in a function definition def hardFunc(arg1, arg2): # create a tuple and pollute it with arguments passed to hardFunc args=(arg1, arg2) # print out results print(args[0]) print(args[1]) hardFunc('hard_one', 'hard_two') # output — Try it yourself now and in sequential snippets! def softFunc(*args): # at this point after calling softFunc a tuple with a name of a word # followed by * is created automatically (in this case the name is args) # print out results print(args[0]) print(args[1]) softFunc('soft_one', 'soft_two') # Now try to do something illegal hardFunc('one', 'two', 'three') # Now do things legally softFunc('one', 'two', 'three') # or even softFunc('one', 'two', 'three', 'infinity') # softFunc handles arbitrary amount of arguments easily by virtue of * syntax # So using a single variable name in conjuction with * we gained the ability # to invoke a function with arbitrary amount of arguments. # Once again when softFunc is called the newly args # tuple filled with provided arguments is created # Conclusion softFunc is a more flexible/dynamic verson of a hardFunc

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